What are the solutions to the equation -3x^2+7x=-5 ?

The solutions to the equation -3x^2+7x=-5 are x=-(-7+sqrt(109))/6 ,x=(7+sqrt(109))/6

Find the zeros of -3x^2+7x=-5

The zeros of -3x^2+7x=-5 are x=-(-7+sqrt(109))/6 ,x=(7+sqrt(109))/6

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- 3 x^{2} + 7 x = - 5

x = - \frac{- 7 + 109}{6}, x = \frac{7 + 109}{6}

Decimal Notation

x = - 0.57338 \dots, x = 2.90671 \dots

Solution steps

- 3 x^{2} + 7 x = - 5

Move

5

to the left side

- 3 x^{2} + 7 x + 5 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 7 \pm 7 ^{2} - 4 ( - 3 ) \cdot 5}{2 ( - 3 )}

7^{2} - 4 (- 3) \cdot 5 = 109

x_{1, 2} = \frac{- 7 \pm 109}{2 ( - 3 )}

Separate the solutions

x_{1} = \frac{- 7 + 109}{2 ( - 3 )}, x_{2} = \frac{- 7 - 109}{2 ( - 3 )}

x = \frac{- 7 + 109}{2 ( - 3 )} : - \frac{- 7 + 109}{6}

x = \frac{- 7 - 109}{2 ( - 3 )} : \frac{7 + 109}{6}

The solutions to the quadratic equation are:

x = - \frac{- 7 + 109}{6}, x = \frac{7 + 109}{6}

(x^{2} + 3 x - 1)^{2} < 9

r^{2} - 36 = 0

(x + h)^{2} - x^{2}

- 4 x - (- 10 + 8 x) = (8 - 16 x) - (14 - 6 x)

a^{2} - 20 a

What are the solutions to the equation -3x^2+7x=-5 ?
The solutions to the equation -3x^2+7x=-5 are x=-(-7+sqrt(109))/6 ,x=(7+sqrt(109))/6
Find the zeros of -3x^2+7x=-5
The zeros of -3x^2+7x=-5 are x=-(-7+sqrt(109))/6 ,x=(7+sqrt(109))/6