What is the answer to |x|+4=12 ?

The answer to |x|+4=12 is x=-8\lor x=8

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|x|+4=12

∣ x ∣ + 4 = 12

x = - 8 or x = 8

Solution steps

∣ x ∣ + 4 = 12

Move

4

to the right side

∣ x ∣ = 8

Apply absolute rule: If

∣ u ∣ = a, a > 0

then

u = a

u = - a

x = - 8 or x = 8

16 - w^{2}

(- \frac{3}{2})^{3}

(x + 1)^{2} - 3 > 0

\frac{x - 3}{4} < \frac{10}{3}

3 t^{2} + t - 7 = 0