What are the solutions to the equation 18(x-3)^2+9(x-3)-2=0 ?

The solutions to the equation 18(x-3)^2+9(x-3)-2=0 are x= 19/6 ,x= 7/3

Find the zeros of 18(x-3)^2+9(x-3)-2=0

The zeros of 18(x-3)^2+9(x-3)-2=0 are x= 19/6 ,x= 7/3

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18 (x - 3)^{2} + 9 (x - 3) - 2 = 0

x = \frac{19}{6}, x = \frac{7}{3}

Decimal Notation

x = 3.16666 \dots, x = 2.33333 \dots

Solution steps

18 (x - 3)^{2} + 9 (x - 3) - 2 = 0

Expand

18 (x - 3)^{2} + 9 (x - 3) - 2 : 18 x^{2} - 99 x + 133

18 x^{2} - 99 x + 133 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 99 ) \pm ( - 99 ) ^{2} - 4 \cdot 18 \cdot 133}{2 \cdot 18}

(- 99)^{2} - 4 \cdot 18 \cdot 133 = 15

x_{1, 2} = \frac{- ( - 99 ) \pm 15}{2 \cdot 18}

Separate the solutions

x_{1} = \frac{- ( - 99 ) + 15}{2 \cdot 18}, x_{2} = \frac{- ( - 99 ) - 15}{2 \cdot 18}

x = \frac{- ( - 99 ) + 15}{2 \cdot 18} : \frac{19}{6}

x = \frac{- ( - 99 ) - 15}{2 \cdot 18} : \frac{7}{3}

The solutions to the quadratic equation are:

x = \frac{19}{6}, x = \frac{7}{3}

- 6 + 9 i

9 - 2 x = 35

(x + 13)^{\frac{3}{2}} + x \cdot \frac{3}{2} (x + 13)^{\frac{1}{2}}

18

∣ x ∣ - 1 > 0

What are the solutions to the equation 18(x-3)^2+9(x-3)-2=0 ?
The solutions to the equation 18(x-3)^2+9(x-3)-2=0 are x= 19/6 ,x= 7/3
Find the zeros of 18(x-3)^2+9(x-3)-2=0
The zeros of 18(x-3)^2+9(x-3)-2=0 are x= 19/6 ,x= 7/3