What is factor x^4-3x^3+x^2+3x-2 ?

The solution to factor x^4-3x^3+x^2+3x-2 is (x-1)^2(x-2)(x+1)

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factor x^4-3x^3+x^2+3x-2

factor

x^{4} - 3 x^{3} + x^{2} + 3 x - 2

(x - 1)^{2} (x - 2) (x + 1)

Solution steps

x^{4} - 3 x^{3} + x^{2} + 3 x - 2

Use the rational root theorem

= (x - 1) \frac{x ^{4} - 3 x ^{3} + x ^{2} + 3 x - 2}{x - 1}

\frac{x ^{4} - 3 x ^{3} + x ^{2} + 3 x - 2}{x - 1} = x^{3} - 2 x^{2} - x + 2

= (x - 1) (x^{3} - 2 x^{2} - x + 2)

Factor

x^{3} - 2 x^{2} - x + 2 : (x - 2) (x + 1) (x - 1)

= (x - 1) (x - 2) (x + 1) (x - 1)

Apply exponent rule:

aa = a^{2}

(x - 1) (x - 1) = (x - 1)^{2}

= (x - 1)^{2} (x - 2) (x + 1)

\frac{x}{9} - 7 = - 8

12 x^{2} - 30 x - 18 = 0

(- \frac{10}{3})^{2}

0.7 (4 x + 8) = 1.1 - (x + 2)

lo g_{3} (\frac{1}{27})

What is factor x^4-3x^3+x^2+3x-2 ?
The solution to factor x^4-3x^3+x^2+3x-2 is (x-1)^2(x-2)(x+1)