What are the solutions to the equation 0=-16x^2+64x+80 ?

The solutions to the equation 0=-16x^2+64x+80 are x=-1,x=5

Find the zeros of 0=-16x^2+64x+80

The zeros of 0=-16x^2+64x+80 are x=-1,x=5

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

0 = - 16 x^{2} + 64 x + 80

x = - 1, x = 5

Solution steps

0 = - 16 x^{2} + 64 x + 80

Switch sides

- 16 x^{2} + 64 x + 80 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 64 \pm 6 4 ^{2} - 4 ( - 16 ) \cdot 80}{2 ( - 16 )}

6 4^{2} - 4 (- 16) \cdot 80 = 96

x_{1, 2} = \frac{- 64 \pm 96}{2 ( - 16 )}

Separate the solutions

x_{1} = \frac{- 64 + 96}{2 ( - 16 )}, x_{2} = \frac{- 64 - 96}{2 ( - 16 )}

x = \frac{- 64 + 96}{2 ( - 16 )} : - 1

x = \frac{- 64 - 96}{2 ( - 16 )} : 5

The solutions to the quadratic equation are:

x = - 1, x = 5

4 k^{2} - 1

\frac{1}{4} t + \frac{1}{2} < \frac{2}{3} t - 2

\frac{33}{2} - \frac{33}{2 ( 10 ) ^{2}}

x^{3} - x^{2} - 4

x + 2 = 3

What are the solutions to the equation 0=-16x^2+64x+80 ?
The solutions to the equation 0=-16x^2+64x+80 are x=-1,x=5
Find the zeros of 0=-16x^2+64x+80
The zeros of 0=-16x^2+64x+80 are x=-1,x=5