What are the solutions to the equation x^2-5x=-9/4 ?

The solutions to the equation x^2-5x=-9/4 are x= 9/2 ,x= 1/2

Find the zeros of x^2-5x=-9/4

The zeros of x^2-5x=-9/4 are x= 9/2 ,x= 1/2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

x^{2} - 5 x = - \frac{9}{4}

x = \frac{9}{2}, x = \frac{1}{2}

Decimal Notation

x = 4.5, x = 0.5

Solution steps

x^{2} - 5 x = - \frac{9}{4}

Multiply both sides by

4

4 x^{2} - 20 x = - 9

Move

9

to the left side

4 x^{2} - 20 x + 9 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 20 ) \pm ( - 20 ) ^{2} - 4 \cdot 4 \cdot 9}{2 \cdot 4}

(- 20)^{2} - 4 \cdot 4 \cdot 9 = 16

x_{1, 2} = \frac{- ( - 20 ) \pm 16}{2 \cdot 4}

Separate the solutions

x_{1} = \frac{- ( - 20 ) + 16}{2 \cdot 4}, x_{2} = \frac{- ( - 20 ) - 16}{2 \cdot 4}

x = \frac{- ( - 20 ) + 16}{2 \cdot 4} : \frac{9}{2}

x = \frac{- ( - 20 ) - 16}{2 \cdot 4} : \frac{1}{2}

The solutions to the quadratic equation are:

x = \frac{9}{2}, x = \frac{1}{2}

7 r^{2} - 10 r = - 5

(3 p^{4})^{3} \cdot (p^{2})^{7}

lo g_{3} (4)

5 \cdot \frac{180}{π}

2 x^{2} - 3 x - 5 = 0

What are the solutions to the equation x^2-5x=-9/4 ?
The solutions to the equation x^2-5x=-9/4 are x= 9/2 ,x= 1/2
Find the zeros of x^2-5x=-9/4
The zeros of x^2-5x=-9/4 are x= 9/2 ,x= 1/2