What are the solutions to the equation h^2+10h-37=0 ?

The solutions to the equation h^2+10h-37=0 are h=-5+sqrt(62),h=-5-sqrt(62)

Find the zeros of h^2+10h-37=0

The zeros of h^2+10h-37=0 are h=-5+sqrt(62),h=-5-sqrt(62)

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h^{2} + 10 h - 37 = 0

h = - 5 + 62, h = - 5 - 62

Decimal Notation

h = 2.87400 \dots, h = - 12.87400 \dots

Solution steps

h^{2} + 10 h - 37 = 0

Solve with the quadratic formula

h_{1, 2} = \frac{- 10 \pm 1 0 ^{2} - 4 \cdot 1 \cdot ( - 37 )}{2 \cdot 1}

1 0^{2} - 4 \cdot 1 \cdot (- 37) = 262

h_{1, 2} = \frac{- 10 \pm 2 62}{2 \cdot 1}

Separate the solutions

h_{1} = \frac{- 10 + 2 62}{2 \cdot 1}, h_{2} = \frac{- 10 - 2 62}{2 \cdot 1}

h = \frac{- 10 + 2 62}{2 \cdot 1} : - 5 + 62

h = \frac{- 10 - 2 62}{2 \cdot 1} : - 5 - 62

The solutions to the quadratic equation are:

h = - 5 + 62, h = - 5 - 62

2 x^{2} + 12 x + 18 = 0

2 x - 1 < \frac{3 x}{2} < x + 1

\frac{3}{26} \cdot 8

330

4 s^{2} - 9 s + 5

What are the solutions to the equation h^2+10h-37=0 ?
The solutions to the equation h^2+10h-37=0 are h=-5+sqrt(62),h=-5-sqrt(62)
Find the zeros of h^2+10h-37=0
The zeros of h^2+10h-37=0 are h=-5+sqrt(62),h=-5-sqrt(62)