What is factor (a+b+1)(a^2+1)-a^2-1 ?

The solution to factor (a+b+1)(a^2+1)-a^2-1 is (a^2+1)(a+b)

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factor (a+b+1)(a^2+1)-a^2-1

factor

(a + b + 1) (a^{2} + 1) - a^{2} - 1

(a^{2} + 1) (a + b)

Solution steps

(a + b + 1) (a^{2} + 1) - a^{2} - 1

Factor

- a^{2} - 1 : - (a^{2} + 1)

= (a + b + 1) (a^{2} + 1) - (a^{2} + 1)

Factor out common term

(a^{2} + 1) : (a^{2} + 1) (a + b)

= (a^{2} + 1) (a + b)

11 = \frac{4000}{127000}

\frac{5}{9} - \frac{9}{5}

\frac{1}{2}

1 + \frac{2 x}{5} - \frac{1}{2} (x + 5) \geq x

12 x - 13 x + 4 - 8 x = 9 - 4 x + 6 x - 2 - 5 x

What is factor (a+b+1)(a^2+1)-a^2-1 ?
The solution to factor (a+b+1)(a^2+1)-a^2-1 is (a^2+1)(a+b)