What is 2(4k^2-2k)-3(-6k^2+4)+2k(k-1) ?

The solution to 2(4k^2-2k)-3(-6k^2+4)+2k(k-1) is 28k^2-6k-12

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simplify 2(4k^2-2k)-3(-6k^2+4)+2k(k-1)

simplify

2 (4 k^{2} - 2 k) - 3 (- 6 k^{2} + 4) + 2 k (k - 1)

28 k^{2} - 6 k - 12

Solution steps

2 (4 k^{2} - 2 k) - 3 (- 6 k^{2} + 4) + 2 k (k - 1)

Expand

2 (4 k^{2} - 2 k) : 8 k^{2} - 4 k

= 8 k^{2} - 4 k - 3 (- 6 k^{2} + 4) + 2 k (k - 1)

Expand

- 3 (- 6 k^{2} + 4) : 18 k^{2} - 12

= 8 k^{2} - 4 k + 18 k^{2} - 12 + 2 k (k - 1)

Expand

2 k (k - 1) : 2 k^{2} - 2 k

= 8 k^{2} - 4 k + 18 k^{2} - 12 + 2 k^{2} - 2 k

Group like terms

= 8 k^{2} + 18 k^{2} + 2 k^{2} - 4 k - 2 k - 12

Add similar elements:

8 k^{2} + 18 k^{2} + 2 k^{2} = 28 k^{2}

= 28 k^{2} - 4 k - 2 k - 12

Add similar elements:

- 4 k - 2 k = - 6 k

= 28 k^{2} - 6 k - 12

45 a^{4} - 30 a^{3} + 5 a^{2}

- \frac{1}{2} x \geq 4

x^{2} + 7 x - 120

3 x^{2} - 2 x < 2 x^{2} + 35

5 = \frac{5 - 2 b}{4} (2)^{2} + b^{2}

What is 2(4k^2-2k)-3(-6k^2+4)+2k(k-1) ?
The solution to 2(4k^2-2k)-3(-6k^2+4)+2k(k-1) is 28k^2-6k-12