What are the solutions to the equation (2x+3)^2=0 ?

The solutions to the equation (2x+3)^2=0 are x=-3/2

Find the zeros of (2x+3)^2=0

The zeros of (2x+3)^2=0 are x=-3/2

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(2 x + 3)^{2} = 0

x = - \frac{3}{2}

Decimal Notation

x = - 1.5

Solution steps

(2 x + 3)^{2} = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

Solve

2 x + 3 = 0 : x = - \frac{3}{2}

The solution to the quadratic equation is:

x = - \frac{3}{2}

- (\frac{3}{4})^{2}

3 r^{2} + 5 r - 2 = 0

- 6 x^{2} - 30 = 0

x^{2} + 4 x + 10 = - 7

7 (x - 2) < 2 x + 3

What are the solutions to the equation (2x+3)^2=0 ?
The solutions to the equation (2x+3)^2=0 are x=-3/2
Find the zeros of (2x+3)^2=0
The zeros of (2x+3)^2=0 are x=-3/2