What are the solutions to the equation y^2+6y+13=0 ?

The solutions to the equation y^2+6y+13=0 are y=-3+2i,y=-3-2i

Find the zeros of y^2+6y+13=0

The zeros of y^2+6y+13=0 are y=-3+2i,y=-3-2i

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y^{2} + 6 y + 13 = 0

y = - 3 + 2 i, y = - 3 - 2 i

Solution steps

y^{2} + 6 y + 13 = 0

Solve with the quadratic formula

y_{1, 2} = \frac{- 6 \pm 6 ^{2} - 4 \cdot 1 \cdot 13}{2 \cdot 1}

Simplify

6^{2} - 4 \cdot 1 \cdot 13 : 4 i

y_{1, 2} = \frac{- 6 \pm 4 i}{2 \cdot 1}

Separate the solutions

y_{1} = \frac{- 6 + 4 i}{2 \cdot 1}, y_{2} = \frac{- 6 - 4 i}{2 \cdot 1}

y = \frac{- 6 + 4 i}{2 \cdot 1} : - 3 + 2 i

y = \frac{- 6 - 4 i}{2 \cdot 1} : - 3 - 2 i

The solutions to the quadratic equation are:

y = - 3 + 2 i, y = - 3 - 2 i

3. 1^{2}

- 15 \times 3 + 5

8 x^{2} - 2 x + 3 = 0

\frac{x - 1}{2} = \frac{3 x - 10}{5} + \frac{x - 2}{3}

3 - \frac{5}{4}

What are the solutions to the equation y^2+6y+13=0 ?
The solutions to the equation y^2+6y+13=0 are y=-3+2i,y=-3-2i
Find the zeros of y^2+6y+13=0
The zeros of y^2+6y+13=0 are y=-3+2i,y=-3-2i