What are the solutions to the equation (2h+8)(h)=60 ?

The solutions to the equation (2h+8)(h)=60 are h=-2+sqrt(34),h=-2-sqrt(34)

Find the zeros of (2h+8)(h)=60

The zeros of (2h+8)(h)=60 are h=-2+sqrt(34),h=-2-sqrt(34)

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(2 h + 8) (h) = 60

h = - 2 + 34, h = - 2 - 34

Decimal Notation

h = 3.83095 \dots, h = - 7.83095 \dots

Solution steps

(2 h + 8) (h) = 60

Expand

(2 h + 8) (h) : 2 h^{2} + 8 h

2 h^{2} + 8 h = 60

Move

60

to the left side

2 h^{2} + 8 h - 60 = 0

Solve with the quadratic formula

h_{1, 2} = \frac{- 8 \pm 8 ^{2} - 4 \cdot 2 ( - 60 )}{2 \cdot 2}

8^{2} - 4 \cdot 2 (- 60) = 434

h_{1, 2} = \frac{- 8 \pm 4 34}{2 \cdot 2}

Separate the solutions

h_{1} = \frac{- 8 + 4 34}{2 \cdot 2}, h_{2} = \frac{- 8 - 4 34}{2 \cdot 2}

h = \frac{- 8 + 4 34}{2 \cdot 2} : - 2 + 34

h = \frac{- 8 - 4 34}{2 \cdot 2} : - 2 - 34

The solutions to the quadratic equation are:

h = - 2 + 34, h = - 2 - 34

3 x^{2} - 16 x - 7 = 5

z - 10 = 20

\frac{1}{n} - \frac{1}{n + 1}

∣ 2 x - 3 ∣ = 8

y - 64 \geq - 128

What are the solutions to the equation (2h+8)(h)=60 ?
The solutions to the equation (2h+8)(h)=60 are h=-2+sqrt(34),h=-2-sqrt(34)
Find the zeros of (2h+8)(h)=60
The zeros of (2h+8)(h)=60 are h=-2+sqrt(34),h=-2-sqrt(34)