What is |x+1|>= |1-2x| ?

The solution to |x+1|>= |1-2x| is 0<= x<= 2

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|x+1|>= |1-2x|

∣ x + 1 ∣ \geq ∣ 1 - 2 x ∣

0 \leq x \leq 2

Interval Notation

[0, 2]

Solution steps

∣ x + 1 ∣ \geq ∣ 1 - 2 x ∣

Find positive and negative intervals

x < - 1, - 1 \leq x \leq \frac{1}{2}, x > \frac{1}{2}

Solve the inequality for each interval

No Solution or 0 \leq x \leq \frac{1}{2} or \frac{1}{2} < x \leq 2

Merge Overlapping Intervals

0 \leq x \leq 2

64 + 27 a^{3}

\frac{r ^{2}}{r ^{- 6}}

\frac{7}{10} + \frac{3}{5}

\frac{3}{16} + \frac{3}{8}

- 4 \cdot 1