What are the solutions to the equation -x^2-2x-1=0 ?

The solutions to the equation -x^2-2x-1=0 are x=-1

Find the zeros of -x^2-2x-1=0

The zeros of -x^2-2x-1=0 are x=-1

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- x^{2} - 2 x - 1 = 0

x = - 1

Solution steps

- x^{2} - 2 x - 1 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 2 ) \pm ( - 2 ) ^{2} - 4 ( - 1 ) ( - 1 )}{2 ( - 1 )}

(- 2)^{2} - 4 (- 1) (- 1) = 0

x_{1, 2} = \frac{- ( - 2 ) \pm 0}{2 ( - 1 )}

x = \frac{- ( - 2 )}{2 ( - 1 )}

\frac{- ( - 2 )}{2 ( - 1 )} = - 1

x = - 1

The solution to the quadratic equation is:

x = - 1

24 x^{2} + 4 x - 4

25!

100 x^{2} - 169 \leq 0

(x + 1)^{2} > 0

4 s^{2} - 25

What are the solutions to the equation -x^2-2x-1=0 ?
The solutions to the equation -x^2-2x-1=0 are x=-1
Find the zeros of -x^2-2x-1=0
The zeros of -x^2-2x-1=0 are x=-1