What are the solutions to the equation 2a^2+12a=-22 ?

The solutions to the equation 2a^2+12a=-22 are a=-3+sqrt(2)i,a=-3-sqrt(2)i

Find the zeros of 2a^2+12a=-22

The zeros of 2a^2+12a=-22 are a=-3+sqrt(2)i,a=-3-sqrt(2)i

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2 a^{2} + 12 a = - 22

a = - 3 + 2 i, a = - 3 - 2 i

Solution steps

2 a^{2} + 12 a = - 22

Move

22

to the left side

2 a^{2} + 12 a + 22 = 0

Solve with the quadratic formula

a_{1, 2} = \frac{- 12 \pm 1 2 ^{2} - 4 \cdot 2 \cdot 22}{2 \cdot 2}

Simplify

1 2^{2} - 4 \cdot 2 \cdot 22 : 42 i

a_{1, 2} = \frac{- 12 \pm 4 2 i}{2 \cdot 2}

Separate the solutions

a_{1} = \frac{- 12 + 4 2 i}{2 \cdot 2}, a_{2} = \frac{- 12 - 4 2 i}{2 \cdot 2}

a = \frac{- 12 + 4 2 i}{2 \cdot 2} : - 3 + 2 i

a = \frac{- 12 - 4 2 i}{2 \cdot 2} : - 3 - 2 i

The solutions to the quadratic equation are:

a = - 3 + 2 i, a = - 3 - 2 i

ln (3) + ln (4)

∣ x + 5 ∣ = ∣ 5 - x ∣

2 q x^{2} + pq x - 8 x - 4 p

5 x + 34 \leq 23

6 < x \leq 0

What are the solutions to the equation 2a^2+12a=-22 ?
The solutions to the equation 2a^2+12a=-22 are a=-3+sqrt(2)i,a=-3-sqrt(2)i
Find the zeros of 2a^2+12a=-22
The zeros of 2a^2+12a=-22 are a=-3+sqrt(2)i,a=-3-sqrt(2)i