What is (x+2)(x-5)+2>= (x-1)(x-10) ?

The solution to (x+2)(x-5)+2>= (x-1)(x-10) is x>= 9/4

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(x+2)(x-5)+2>= (x-1)(x-10)

(x + 2) (x - 5) + 2 \geq (x - 1) (x - 10)

x \geq \frac{9}{4}

Interval Notation

[\frac{9}{4}, \infty)

Decimal Notation

x \geq 2.25

Solution steps

(x + 2) (x - 5) + 2 \geq (x - 1) (x - 10)

Rewrite in standard form

4 x - 9 \geq 0

Move

9

to the right side

4 x \geq 9

Divide both sides by

4

x \geq \frac{9}{4}

5 x - 1 = x + 27

16 a^{2} - 4 b^{2}

x^{2} (x^{2} - 49) - 25 (x^{2} - 49)

10 (7 x + 10) = 1

5 x + 8 = 2 x - 19

What is (x+2)(x-5)+2>= (x-1)(x-10) ?
The solution to (x+2)(x-5)+2>= (x-1)(x-10) is x>= 9/4