What are the solutions to the equation n^2+5n+1=3n ?

The solutions to the equation n^2+5n+1=3n are n=-1

Find the zeros of n^2+5n+1=3n

The zeros of n^2+5n+1=3n are n=-1

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n^{2} + 5 n + 1 = 3 n

n = - 1

Solution steps

n^{2} + 5 n + 1 = 3 n

Move

3 n

to the left side

n^{2} + 2 n + 1 = 0

Solve with the quadratic formula

n_{1, 2} = \frac{- 2 \pm 2 ^{2} - 4 \cdot 1 \cdot 1}{2 \cdot 1}

2^{2} - 4 \cdot 1 \cdot 1 = 0

n_{1, 2} = \frac{- 2 \pm 0}{2 \cdot 1}

n = \frac{- 2}{2 \cdot 1}

\frac{- 2}{2 \cdot 1} = - 1

n = - 1

The solution to the quadratic equation is:

n = - 1

\frac{x + 5}{45} = \frac{x - 9}{36}

32 = \frac{9}{5} c + 32

7 (4 a - 8) = 3 (- a + 2)

\frac{6 + 5 i}{- 2 i}

5 + e^{x} > 10

What are the solutions to the equation n^2+5n+1=3n ?
The solutions to the equation n^2+5n+1=3n are n=-1
Find the zeros of n^2+5n+1=3n
The zeros of n^2+5n+1=3n are n=-1