What are the solutions to the equation 3x^2+10x-1=0 ?

The solutions to the equation 3x^2+10x-1=0 are x=(-5+2sqrt(7))/3 ,x=-(5+2sqrt(7))/3

Find the zeros of 3x^2+10x-1=0

The zeros of 3x^2+10x-1=0 are x=(-5+2sqrt(7))/3 ,x=-(5+2sqrt(7))/3

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3 x^{2} + 10 x - 1 = 0

x = \frac{- 5 + 2 7}{3}, x = - \frac{5 + 2 7}{3}

Decimal Notation

x = 0.09716 \dots, x = - 3.43050 \dots

Solution steps

3 x^{2} + 10 x - 1 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 10 \pm 1 0 ^{2} - 4 \cdot 3 ( - 1 )}{2 \cdot 3}

1 0^{2} - 4 \cdot 3 (- 1) = 47

x_{1, 2} = \frac{- 10 \pm 4 7}{2 \cdot 3}

Separate the solutions

x_{1} = \frac{- 10 + 4 7}{2 \cdot 3}, x_{2} = \frac{- 10 - 4 7}{2 \cdot 3}

x = \frac{- 10 + 4 7}{2 \cdot 3} : \frac{- 5 + 2 7}{3}

x = \frac{- 10 - 4 7}{2 \cdot 3} : - \frac{5 + 2 7}{3}

The solutions to the quadratic equation are:

x = \frac{- 5 + 2 7}{3}, x = - \frac{5 + 2 7}{3}

\frac{x}{- 15} < - 4

v^{2} + 6 v - 7

\frac{( 2 a ^{2} b ^{4} ) ^{3}}{4 a ^{3} b ^{7}}

k^{2} + k + 1 = 0

(- 3) (2 x - 2) < (- 3) (2)

What are the solutions to the equation 3x^2+10x-1=0 ?
The solutions to the equation 3x^2+10x-1=0 are x=(-5+2sqrt(7))/3 ,x=-(5+2sqrt(7))/3
Find the zeros of 3x^2+10x-1=0
The zeros of 3x^2+10x-1=0 are x=(-5+2sqrt(7))/3 ,x=-(5+2sqrt(7))/3