What are the solutions to the equation 3x^2-3x-2=0 ?

The solutions to the equation 3x^2-3x-2=0 are x=(3+sqrt(33))/6 ,x=(3-sqrt(33))/6

Find the zeros of 3x^2-3x-2=0

The zeros of 3x^2-3x-2=0 are x=(3+sqrt(33))/6 ,x=(3-sqrt(33))/6

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3 x^{2} - 3 x - 2 = 0

x = \frac{3 + 33}{6}, x = \frac{3 - 33}{6}

Decimal Notation

x = 1.45742 \dots, x = - 0.45742 \dots

Solution steps

3 x^{2} - 3 x - 2 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 3 ) \pm ( - 3 ) ^{2} - 4 \cdot 3 ( - 2 )}{2 \cdot 3}

(- 3)^{2} - 4 \cdot 3 (- 2) = 33

x_{1, 2} = \frac{- ( - 3 ) \pm 33}{2 \cdot 3}

Separate the solutions

x_{1} = \frac{- ( - 3 ) + 33}{2 \cdot 3}, x_{2} = \frac{- ( - 3 ) - 33}{2 \cdot 3}

x = \frac{- ( - 3 ) + 33}{2 \cdot 3} : \frac{3 + 33}{6}

x = \frac{- ( - 3 ) - 33}{2 \cdot 3} : \frac{3 - 33}{6}

The solutions to the quadratic equation are:

x = \frac{3 + 33}{6}, x = \frac{3 - 33}{6}

3 c^{7} + 5 c^{3} + 8 c^{5}

\frac{x}{8} = 5

x^{2} y^{3} - 11 x^{2} y + 6 y^{2} - 66

f = 2^{1}

What are the solutions to the equation 3x^2-3x-2=0 ?
The solutions to the equation 3x^2-3x-2=0 are x=(3+sqrt(33))/6 ,x=(3-sqrt(33))/6
Find the zeros of 3x^2-3x-2=0
The zeros of 3x^2-3x-2=0 are x=(3+sqrt(33))/6 ,x=(3-sqrt(33))/6