What are the solutions to the equation 15x^2-3x=3-7x ?

The solutions to the equation 15x^2-3x=3-7x are x= 1/3 ,x=-3/5

Find the zeros of 15x^2-3x=3-7x

The zeros of 15x^2-3x=3-7x are x= 1/3 ,x=-3/5

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15 x^{2} - 3 x = 3 - 7 x

x = \frac{1}{3}, x = - \frac{3}{5}

Decimal Notation

x = 0.33333 \dots, x = - 0.6

Solution steps

15 x^{2} - 3 x = 3 - 7 x

Move

7 x

to the left side

15 x^{2} + 4 x = 3

Move

3

to the left side

15 x^{2} + 4 x - 3 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 4 \pm 4 ^{2} - 4 \cdot 15 ( - 3 )}{2 \cdot 15}

4^{2} - 4 \cdot 15 (- 3) = 14

x_{1, 2} = \frac{- 4 \pm 14}{2 \cdot 15}

Separate the solutions

x_{1} = \frac{- 4 + 14}{2 \cdot 15}, x_{2} = \frac{- 4 - 14}{2 \cdot 15}

x = \frac{- 4 + 14}{2 \cdot 15} : \frac{1}{3}

x = \frac{- 4 - 14}{2 \cdot 15} : - \frac{3}{5}

The solutions to the quadratic equation are:

x = \frac{1}{3}, x = - \frac{3}{5}

6 x^{2} + 11 x + 3 = 0

- 2 x + 12 < - 4

x^{3} + x^{2} + 16 x + 16 > 0

x^{2} - 19 x - 42

- 5 x + 3 = x + 9

What are the solutions to the equation 15x^2-3x=3-7x ?
The solutions to the equation 15x^2-3x=3-7x are x= 1/3 ,x=-3/5
Find the zeros of 15x^2-3x=3-7x
The zeros of 15x^2-3x=3-7x are x= 1/3 ,x=-3/5