What is 1/(x-2)>= 3/(x+1) ?

The solution to 1/(x-2)>= 3/(x+1) is x<-1\lor 2<x<= 7/2

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1/(x-2)>= 3/(x+1)

\frac{1}{x - 2} \geq \frac{3}{x + 1}

x < - 1 or 2 < x \leq \frac{7}{2}

Interval Notation

(- \infty, - 1) \cup (2, \frac{7}{2}]

Decimal Notation

x < - 1 or 2 < x \leq 3.5

Solution steps

\frac{1}{x - 2} \geq \frac{3}{x + 1}

Rewrite in standard form

\frac{- 2 x + 7}{( x - 2 ) ( x + 1 )} \geq 0

Identify the intervals

x < - 1 or 2 < x \leq \frac{7}{2}

6 x - 8 = 8 x - 6

6 - 2 x = 3

lo g_{6} (1)

\frac{5}{20}

x^{2} + 7 = 43

What is 1/(x-2)>= 3/(x+1) ?
The solution to 1/(x-2)>= 3/(x+1) is x<-1\lor 2<x<= 7/2