What are the solutions to the equation 2x^2-x-4=2 ?

The solutions to the equation 2x^2-x-4=2 are x=2,x=-3/2

Find the zeros of 2x^2-x-4=2

The zeros of 2x^2-x-4=2 are x=2,x=-3/2

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2 x^{2} - x - 4 = 2

x = 2, x = - \frac{3}{2}

Decimal Notation

x = 2, x = - 1.5

Solution steps

2 x^{2} - x - 4 = 2

Move

2

to the left side

2 x^{2} - x - 6 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 1 ) \pm ( - 1 ) ^{2} - 4 \cdot 2 ( - 6 )}{2 \cdot 2}

(- 1)^{2} - 4 \cdot 2 (- 6) = 7

x_{1, 2} = \frac{- ( - 1 ) \pm 7}{2 \cdot 2}

Separate the solutions

x_{1} = \frac{- ( - 1 ) + 7}{2 \cdot 2}, x_{2} = \frac{- ( - 1 ) - 7}{2 \cdot 2}

x = \frac{- ( - 1 ) + 7}{2 \cdot 2} : 2

x = \frac{- ( - 1 ) - 7}{2 \cdot 2} : - \frac{3}{2}

The solutions to the quadratic equation are:

x = 2, x = - \frac{3}{2}

(- \frac{3}{4}) (\frac{4}{5})

1 + 2 x < 10

- 10 < \frac{5 - 7 x}{9} \leq 7

- 7 - 2

x + 1 = 5

What are the solutions to the equation 2x^2-x-4=2 ?
The solutions to the equation 2x^2-x-4=2 are x=2,x=-3/2
Find the zeros of 2x^2-x-4=2
The zeros of 2x^2-x-4=2 are x=2,x=-3/2