What is 5(x^0)y^{-1} ?

The solution to 5(x^0)y^{-1} is 5/y

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

simplify 5(x^0)y^{-1}

simplify

5 (x^{0}) y^{- 1}

\frac{5}{y}

Solution steps

5 (x^{0}) y^{- 1}

Apply rule:

(a) = a

(x^{0}) = x^{0}

= 5 x^{0} y^{- 1}

Apply exponent rule:

a^{0} = 1,

assuming

a \neq = 0

x^{0} = 1

= 5 \cdot 1 \cdot y^{- 1}

Apply exponent rule:

a^{- 1} = \frac{1}{a}

y^{- 1} = \frac{1}{y}

= 5 \cdot 1 \cdot \frac{1}{y}

Multiply the numbers:

5 \cdot 1 = 5

= 5 \cdot \frac{1}{y}

Apply the fraction rule:

a \cdot \frac{b}{c} = \frac{a \cdot b}{c}

= \frac{5 \cdot 1}{y}

Multiply the numbers:

5 \cdot 1 = 5

= \frac{5}{y}

n^{2} + 13 n + 36

∣ 9 y - 2 ∣ \geq - 16

84 = 3 (- 5 x - 2)

\frac{3}{x - 2} > 1

e^{x} e^{y}