What are the solutions to the equation 0=x^2-4x ?

The solutions to the equation 0=x^2-4x are x=4,x=0

Find the zeros of 0=x^2-4x

The zeros of 0=x^2-4x are x=4,x=0

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0 = x^{2} - 4 x

x = 4, x = 0

Solution steps

0 = x^{2} - 4 x

Switch sides

x^{2} - 4 x = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 4 ) \pm ( - 4 ) ^{2} - 4 \cdot 1 \cdot 0}{2 \cdot 1}

(- 4)^{2} - 4 \cdot 1 \cdot 0 = 4

x_{1, 2} = \frac{- ( - 4 ) \pm 4}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 4 ) + 4}{2 \cdot 1}, x_{2} = \frac{- ( - 4 ) - 4}{2 \cdot 1}

x = \frac{- ( - 4 ) + 4}{2 \cdot 1} : 4

x = \frac{- ( - 4 ) - 4}{2 \cdot 1} : 0

The solutions to the quadratic equation are:

x = 4, x = 0

- 3 x - 5 = - 2

8 \leq 23 - 3 x

- 1 \leq 1 - p

x^{2} + (2 x + 3)^{2} = 26

x (x - 4) (x + 5) \leq 0

What are the solutions to the equation 0=x^2-4x ?
The solutions to the equation 0=x^2-4x are x=4,x=0
Find the zeros of 0=x^2-4x
The zeros of 0=x^2-4x are x=4,x=0