What are the solutions to the equation 9x^2-2x-1=0 ?

The solutions to the equation 9x^2-2x-1=0 are x=(1+sqrt(10))/9 ,x=(1-sqrt(10))/9

Find the zeros of 9x^2-2x-1=0

The zeros of 9x^2-2x-1=0 are x=(1+sqrt(10))/9 ,x=(1-sqrt(10))/9

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9 x^{2} - 2 x - 1 = 0

x = \frac{1 + 10}{9}, x = \frac{1 - 10}{9}

Decimal Notation

x = 0.46247 \dots, x = - 0.24025 \dots

Solution steps

9 x^{2} - 2 x - 1 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 2 ) \pm ( - 2 ) ^{2} - 4 \cdot 9 ( - 1 )}{2 \cdot 9}

(- 2)^{2} - 4 \cdot 9 (- 1) = 210

x_{1, 2} = \frac{- ( - 2 ) \pm 2 10}{2 \cdot 9}

Separate the solutions

x_{1} = \frac{- ( - 2 ) + 2 10}{2 \cdot 9}, x_{2} = \frac{- ( - 2 ) - 2 10}{2 \cdot 9}

x = \frac{- ( - 2 ) + 2 10}{2 \cdot 9} : \frac{1 + 10}{9}

x = \frac{- ( - 2 ) - 2 10}{2 \cdot 9} : \frac{1 - 10}{9}

The solutions to the quadratic equation are:

x = \frac{1 + 10}{9}, x = \frac{1 - 10}{9}

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\frac{( - 8 x ^{3} y ^{2} ) ^{2} \cdot 2 x ^{2} y ^{6}}{32 x ^{8} y ^{3}}

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7 (y - 8) = 7 y + 42

What are the solutions to the equation 9x^2-2x-1=0 ?
The solutions to the equation 9x^2-2x-1=0 are x=(1+sqrt(10))/9 ,x=(1-sqrt(10))/9
Find the zeros of 9x^2-2x-1=0
The zeros of 9x^2-2x-1=0 are x=(1+sqrt(10))/9 ,x=(1-sqrt(10))/9