What are the solutions to the equation 3x^2+24x+54=6 ?

The solutions to the equation 3x^2+24x+54=6 are x=-4

Find the zeros of 3x^2+24x+54=6

The zeros of 3x^2+24x+54=6 are x=-4

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3 x^{2} + 24 x + 54 = 6

x = - 4

Solution steps

3 x^{2} + 24 x + 54 = 6

Move

6

to the left side

3 x^{2} + 24 x + 48 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 24 \pm 2 4 ^{2} - 4 \cdot 3 \cdot 48}{2 \cdot 3}

2 4^{2} - 4 \cdot 3 \cdot 48 = 0

x_{1, 2} = \frac{- 24 \pm 0}{2 \cdot 3}

x = \frac{- 24}{2 \cdot 3}

\frac{- 24}{2 \cdot 3} = - 4

x = - 4

The solution to the quadratic equation is:

x = - 4

3 x = 24

12 + 9 j + j \leq 72

- 4 (- 3) 2 + 4 - (6 - 2)

64 x^{2} + 32 x y - 21 y^{2}

12!

What are the solutions to the equation 3x^2+24x+54=6 ?
The solutions to the equation 3x^2+24x+54=6 are x=-4
Find the zeros of 3x^2+24x+54=6
The zeros of 3x^2+24x+54=6 are x=-4