What are the solutions to the equation -2.5x^2+12x+21=0 ?

The solutions to the equation -2.5x^2+12x+21=0 are x=-(-12+sqrt(354))/5 ,x=(12+sqrt(354))/5

Find the zeros of -2.5x^2+12x+21=0

The zeros of -2.5x^2+12x+21=0 are x=-(-12+sqrt(354))/5 ,x=(12+sqrt(354))/5

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- 2.5 x^{2} + 12 x + 21 = 0

x = - \frac{- 12 + 354}{5}, x = \frac{12 + 354}{5}

Decimal Notation

x = - 1.36297 \dots, x = 6.16297 \dots

Solution steps

- 2.5 x^{2} + 12 x + 21 = 0

Multiply both sides by

10

- 25 x^{2} + 120 x + 210 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 120 \pm 12 0 ^{2} - 4 ( - 25 ) \cdot 210}{2 ( - 25 )}

12 0^{2} - 4 (- 25) \cdot 210 = 10354

x_{1, 2} = \frac{- 120 \pm 10 354}{2 ( - 25 )}

Separate the solutions

x_{1} = \frac{- 120 + 10 354}{2 ( - 25 )}, x_{2} = \frac{- 120 - 10 354}{2 ( - 25 )}

x = \frac{- 120 + 10 354}{2 ( - 25 )} : - \frac{- 12 + 354}{5}

x = \frac{- 120 - 10 354}{2 ( - 25 )} : \frac{12 + 354}{5}

The solutions to the quadratic equation are:

x = - \frac{- 12 + 354}{5}, x = \frac{12 + 354}{5}

x^{2} + 4 x - 5 \geq 0

- (6 - 2 x) = 4 (x + 1) - 2 x - 10

\frac{2 - 5 i}{i}

1^{\frac{2}{3}}

∣ b ∣ < 3

What are the solutions to the equation -2.5x^2+12x+21=0 ?
The solutions to the equation -2.5x^2+12x+21=0 are x=-(-12+sqrt(354))/5 ,x=(12+sqrt(354))/5
Find the zeros of -2.5x^2+12x+21=0
The zeros of -2.5x^2+12x+21=0 are x=-(-12+sqrt(354))/5 ,x=(12+sqrt(354))/5