What are the solutions to the equation 3x^2+7x-12=0 ?

The solutions to the equation 3x^2+7x-12=0 are x=(-7+sqrt(193))/6 ,x=(-7-sqrt(193))/6

Find the zeros of 3x^2+7x-12=0

The zeros of 3x^2+7x-12=0 are x=(-7+sqrt(193))/6 ,x=(-7-sqrt(193))/6

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3 x^{2} + 7 x - 12 = 0

x = \frac{- 7 + 193}{6}, x = \frac{- 7 - 193}{6}

Decimal Notation

x = 1.14874 \dots, x = - 3.48207 \dots

Solution steps

3 x^{2} + 7 x - 12 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 7 \pm 7 ^{2} - 4 \cdot 3 ( - 12 )}{2 \cdot 3}

7^{2} - 4 \cdot 3 (- 12) = 193

x_{1, 2} = \frac{- 7 \pm 193}{2 \cdot 3}

Separate the solutions

x_{1} = \frac{- 7 + 193}{2 \cdot 3}, x_{2} = \frac{- 7 - 193}{2 \cdot 3}

x = \frac{- 7 + 193}{2 \cdot 3} : \frac{- 7 + 193}{6}

x = \frac{- 7 - 193}{2 \cdot 3} : \frac{- 7 - 193}{6}

The solutions to the quadratic equation are:

x = \frac{- 7 + 193}{6}, x = \frac{- 7 - 193}{6}

∣ 5 x - 2 ∣ + 8 = 2

\frac{1}{2} - \frac{5}{9}

\frac{7 - 3 i}{5 - 2 i}

3 x^{2} + \frac{3 x}{2} = \frac{x}{3} - x + \frac{37}{3} + x^{2}

- 8 = 8 (- 3 + a)

What are the solutions to the equation 3x^2+7x-12=0 ?
The solutions to the equation 3x^2+7x-12=0 are x=(-7+sqrt(193))/6 ,x=(-7-sqrt(193))/6
Find the zeros of 3x^2+7x-12=0
The zeros of 3x^2+7x-12=0 are x=(-7+sqrt(193))/6 ,x=(-7-sqrt(193))/6