What are the solutions to the equation 2x^2+23=14x ?

The solutions to the equation 2x^2+23=14x are x=(7+sqrt(3))/2 ,x=(7-sqrt(3))/2

Find the zeros of 2x^2+23=14x

The zeros of 2x^2+23=14x are x=(7+sqrt(3))/2 ,x=(7-sqrt(3))/2

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2 x^{2} + 23 = 14 x

x = \frac{7 + 3}{2}, x = \frac{7 - 3}{2}

Decimal Notation

x = 4.36602 \dots, x = 2.63397 \dots

Solution steps

2 x^{2} + 23 = 14 x

Move

14 x

to the left side

2 x^{2} + 23 - 14 x = 0

Write in the standard form

a x^{2} + b x + c = 0

2 x^{2} - 14 x + 23 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 14 ) \pm ( - 14 ) ^{2} - 4 \cdot 2 \cdot 23}{2 \cdot 2}

(- 14)^{2} - 4 \cdot 2 \cdot 23 = 23

x_{1, 2} = \frac{- ( - 14 ) \pm 2 3}{2 \cdot 2}

Separate the solutions

x_{1} = \frac{- ( - 14 ) + 2 3}{2 \cdot 2}, x_{2} = \frac{- ( - 14 ) - 2 3}{2 \cdot 2}

x = \frac{- ( - 14 ) + 2 3}{2 \cdot 2} : \frac{7 + 3}{2}

x = \frac{- ( - 14 ) - 2 3}{2 \cdot 2} : \frac{7 - 3}{2}

The solutions to the quadratic equation are:

x = \frac{7 + 3}{2}, x = \frac{7 - 3}{2}

\frac{5}{6} x = 3

z^{3} + 12 z^{2} + 27 z - 40

3 (n + 2) = 9 (6 - n)

1 - a \leq - 1

3 c^{2} + 45 c + 150

What are the solutions to the equation 2x^2+23=14x ?
The solutions to the equation 2x^2+23=14x are x=(7+sqrt(3))/2 ,x=(7-sqrt(3))/2
Find the zeros of 2x^2+23=14x
The zeros of 2x^2+23=14x are x=(7+sqrt(3))/2 ,x=(7-sqrt(3))/2