What are the solutions to the equation 25x^2+25x+6=0 ?

The solutions to the equation 25x^2+25x+6=0 are x=-2/5 ,x=-3/5

Find the zeros of 25x^2+25x+6=0

The zeros of 25x^2+25x+6=0 are x=-2/5 ,x=-3/5

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25 x^{2} + 25 x + 6 = 0

x = - \frac{2}{5}, x = - \frac{3}{5}

Decimal Notation

x = - 0.4, x = - 0.6

Solution steps

25 x^{2} + 25 x + 6 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 25 \pm 2 5 ^{2} - 4 \cdot 25 \cdot 6}{2 \cdot 25}

2 5^{2} - 4 \cdot 25 \cdot 6 = 5

x_{1, 2} = \frac{- 25 \pm 5}{2 \cdot 25}

Separate the solutions

x_{1} = \frac{- 25 + 5}{2 \cdot 25}, x_{2} = \frac{- 25 - 5}{2 \cdot 25}

x = \frac{- 25 + 5}{2 \cdot 25} : - \frac{2}{5}

x = \frac{- 25 - 5}{2 \cdot 25} : - \frac{3}{5}

The solutions to the quadratic equation are:

x = - \frac{2}{5}, x = - \frac{3}{5}

x^{2} + 7 x + 17 = 5

2 x^{2} + x

\frac{m ( 161 + ( m - 1 ) ( - 7 ) )}{2 ( 161 )} = 0

\frac{1}{2} 4^{- \frac{1}{2}}

ln (- 7)

What are the solutions to the equation 25x^2+25x+6=0 ?
The solutions to the equation 25x^2+25x+6=0 are x=-2/5 ,x=-3/5
Find the zeros of 25x^2+25x+6=0
The zeros of 25x^2+25x+6=0 are x=-2/5 ,x=-3/5