What are the solutions to the equation 6y^2+36=30y ?

The solutions to the equation 6y^2+36=30y are y=3,y=2

Find the zeros of 6y^2+36=30y

The zeros of 6y^2+36=30y are y=3,y=2

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6 y^{2} + 36 = 30 y

y = 3, y = 2

Solution steps

6 y^{2} + 36 = 30 y

Move

30 y

to the left side

6 y^{2} + 36 - 30 y = 0

Write in the standard form

a x^{2} + b x + c = 0

6 y^{2} - 30 y + 36 = 0

Solve with the quadratic formula

y_{1, 2} = \frac{- ( - 30 ) \pm ( - 30 ) ^{2} - 4 \cdot 6 \cdot 36}{2 \cdot 6}

(- 30)^{2} - 4 \cdot 6 \cdot 36 = 6

y_{1, 2} = \frac{- ( - 30 ) \pm 6}{2 \cdot 6}

Separate the solutions

y_{1} = \frac{- ( - 30 ) + 6}{2 \cdot 6}, y_{2} = \frac{- ( - 30 ) - 6}{2 \cdot 6}

y = \frac{- ( - 30 ) + 6}{2 \cdot 6} : 3

y = \frac{- ( - 30 ) - 6}{2 \cdot 6} : 2

The solutions to the quadratic equation are:

y = 3, y = 2

\frac{104 i}{5 + i}

- 5 + \frac{1}{4}

- 3 z - 3 < - 24

\frac{1 2 ^{3}}{2 ^{3}}

(x - 1) (x + 3) \leq 0

What are the solutions to the equation 6y^2+36=30y ?
The solutions to the equation 6y^2+36=30y are y=3,y=2
Find the zeros of 6y^2+36=30y
The zeros of 6y^2+36=30y are y=3,y=2