What are the solutions to the equation 5x^2+4x-9=0 ?

The solutions to the equation 5x^2+4x-9=0 are x=1,x=-9/5

Find the zeros of 5x^2+4x-9=0

The zeros of 5x^2+4x-9=0 are x=1,x=-9/5

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5 x^{2} + 4 x - 9 = 0

x = 1, x = - \frac{9}{5}

Decimal Notation

x = 1, x = - 1.8

Solution steps

5 x^{2} + 4 x - 9 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 4 \pm 4 ^{2} - 4 \cdot 5 ( - 9 )}{2 \cdot 5}

4^{2} - 4 \cdot 5 (- 9) = 14

x_{1, 2} = \frac{- 4 \pm 14}{2 \cdot 5}

Separate the solutions

x_{1} = \frac{- 4 + 14}{2 \cdot 5}, x_{2} = \frac{- 4 - 14}{2 \cdot 5}

x = \frac{- 4 + 14}{2 \cdot 5} : 1

x = \frac{- 4 - 14}{2 \cdot 5} : - \frac{9}{5}

The solutions to the quadratic equation are:

x = 1, x = - \frac{9}{5}

7 + 3 \cdot 4 - 2

\frac{1}{18}

x^{2} (x^{2} - 1) - 9 (x^{2} - 1)

2 x^{2} - 6 x y - 8 y^{2}

2 - \frac{1}{8}

What are the solutions to the equation 5x^2+4x-9=0 ?
The solutions to the equation 5x^2+4x-9=0 are x=1,x=-9/5
Find the zeros of 5x^2+4x-9=0
The zeros of 5x^2+4x-9=0 are x=1,x=-9/5