What is (x)^{-2}(16x^3)(8^{2/3})^{-1} ?

The solution to (x)^{-2}(16x^3)(8^{2/3})^{-1} is 4x

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simplify (x)^{-2}(16x^3)(8^{2/3})^{-1}

simplify

(x)^{- 2} (16 x^{3}) (8^{\frac{2}{3}})^{- 1}

4 x

Solution steps

x^{- 2} (16 x^{3}) (8^{\frac{2}{3}})^{- 1}

Apply exponent rule:

a^{- b} = \frac{1}{a ^{b}}

x^{- 2} = \frac{1}{x ^{2}}

= \frac{1}{x ^{2}} \cdot 16 x^{3} (8^{\frac{2}{3}})^{- 1}

(8^{\frac{2}{3}})^{- 1} = \frac{1}{4}

= \frac{1}{x ^{2}} \cdot 16 x^{3} \frac{1}{4}

Apply the fraction rule:

a \cdot \frac{b}{c} \cdot \frac{d}{e} = \frac{a \cdot b \cdot d}{c \cdot e}

= \frac{1 \cdot 16 x ^{3} \cdot 1}{x ^{2} \cdot 4}

Multiply the numbers:

1 \cdot 16 \cdot 1 = 16

= \frac{16 x ^{3}}{x ^{2} \cdot 4}

Factor the number:

16 = 4 \cdot 4

= \frac{4 \cdot 4 x ^{3}}{x ^{2} \cdot 4}

Cancel the common factor:

4

= \frac{4 x ^{3}}{x ^{2}}

Simplify

\frac{x ^{3}}{x ^{2}} : x

= 4 x

4 d - 11 = 2 d + 7

3 x^{2} = - 21

x^{2} - 3 x < 2 x^{2} - 5 x + 6

x^{3} - x^{2} - 9 x + 9

6 x + 7 = 3 x - 6

What is (x)^{-2}(16x^3)(8^{2/3})^{-1} ?
The solution to (x)^{-2}(16x^3)(8^{2/3})^{-1} is 4x