What is the answer to |x+1|=x^2-5 ?

The answer to |x+1|=x^2-5 is x=(-1-sqrt(17))/2 \lor x=3

Solve for x: |x+1|=x^2-5

The solution is x=(-1-sqrt(17))/2 \lor x=3

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∣ x + 1 ∣ = x^{2} - 5

x = \frac{- 1 - 17}{2} or x = 3

Decimal Notation

x = - 2.56155 \dots, x = 3

Solution steps

∣ x + 1 ∣ = x^{2} - 5

Find positive and negative intervals

x < - 1, x \geq - 1

Solve the inequality for each interval

x = \frac{- 1 - 17}{2} or x = 3

y = y (1 - y)

8 x^{2} - 10 x - 7 = 0

\frac{x ^{- 6}}{x ^{- 9}}

x^{4} - x^{3} - 39 x^{2} + 109 x - 70

What is the answer to |x+1|=x^2-5 ?
The answer to |x+1|=x^2-5 is x=(-1-sqrt(17))/2 \lor x=3
Solve for x: |x+1|=x^2-5
The solution is x=(-1-sqrt(17))/2 \lor x=3