What is the answer to 3(x-2)-5(2x-1)-2(3x+4)+10=0 ?

The answer to 3(x-2)-5(2x-1)-2(3x+4)+10=0 is x= 1/13

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3(x-2)-5(2x-1)-2(3x+4)+10=0

3 (x - 2) - 5 (2 x - 1) - 2 (3 x + 4) + 10 = 0

x = \frac{1}{13}

Solution steps

3 (x - 2) - 5 (2 x - 1) - 2 (3 x + 4) + 10 = 0

Move

10

to the right side

3 (x - 2) - 5 (2 x - 1) - 2 (3 x + 4) = - 10

Expand

3 (x - 2) - 5 (2 x - 1) - 2 (3 x + 4) : - 13 x - 9

- 13 x - 9 = - 10

Move

9

to the right side

- 13 x = - 1

Divide both sides by

- 13

x = \frac{1}{13}

2 x = 2

3 - (\frac{1}{2})

p^{6} q^{4} - q^{7}

\frac{X}{3} \geq 33

b - 7 + 6 \leq 12

What is the answer to 3(x-2)-5(2x-1)-2(3x+4)+10=0 ?
The answer to 3(x-2)-5(2x-1)-2(3x+4)+10=0 is x= 1/13
Solve for x: 3(x-2)-5(2x-1)-2(3x+4)+10=0
The solution is x= 1/13