What are the solutions to the equation 5x^2+2x+5=0 ?

The solutions to the equation 5x^2+2x+5=0 are x=-1/5+i(2sqrt(6))/5 ,x=-1/5-i(2sqrt(6))/5

Find the zeros of 5x^2+2x+5=0

The zeros of 5x^2+2x+5=0 are x=-1/5+i(2sqrt(6))/5 ,x=-1/5-i(2sqrt(6))/5

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5 x^{2} + 2 x + 5 = 0

x = - \frac{1}{5} + i \frac{2 6}{5}, x = - \frac{1}{5} - i \frac{2 6}{5}

Solution steps

5 x^{2} + 2 x + 5 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 2 \pm 2 ^{2} - 4 \cdot 5 \cdot 5}{2 \cdot 5}

Simplify

2^{2} - 4 \cdot 5 \cdot 5 : 46 i

x_{1, 2} = \frac{- 2 \pm 4 6 i}{2 \cdot 5}

Separate the solutions

x_{1} = \frac{- 2 + 4 6 i}{2 \cdot 5}, x_{2} = \frac{- 2 - 4 6 i}{2 \cdot 5}

x = \frac{- 2 + 4 6 i}{2 \cdot 5} : - \frac{1}{5} + i \frac{2 6}{5}

x = \frac{- 2 - 4 6 i}{2 \cdot 5} : - \frac{1}{5} - i \frac{2 6}{5}

The solutions to the quadratic equation are:

x = - \frac{1}{5} + i \frac{2 6}{5}, x = - \frac{1}{5} - i \frac{2 6}{5}

6^{2} + b^{2} = 7^{2}

8^{- 2} = \frac{1}{64}

2 x + 5 = - 7

\frac{m}{- 8} \leq - 2.4

3 \cdot 1 0^{9}

What are the solutions to the equation 5x^2+2x+5=0 ?
The solutions to the equation 5x^2+2x+5=0 are x=-1/5+i(2sqrt(6))/5 ,x=-1/5-i(2sqrt(6))/5
Find the zeros of 5x^2+2x+5=0
The zeros of 5x^2+2x+5=0 are x=-1/5+i(2sqrt(6))/5 ,x=-1/5-i(2sqrt(6))/5