What are the solutions to the equation 5x^2-x-1=0 ?

The solutions to the equation 5x^2-x-1=0 are x=(1+sqrt(21))/(10),x=(1-sqrt(21))/(10)

Find the zeros of 5x^2-x-1=0

The zeros of 5x^2-x-1=0 are x=(1+sqrt(21))/(10),x=(1-sqrt(21))/(10)

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5 x^{2} - x - 1 = 0

x = \frac{1 + 21}{10}, x = \frac{1 - 21}{10}

Decimal Notation

x = 0.55825 \dots, x = - 0.35825 \dots

Solution steps

5 x^{2} - x - 1 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 1 ) \pm ( - 1 ) ^{2} - 4 \cdot 5 ( - 1 )}{2 \cdot 5}

(- 1)^{2} - 4 \cdot 5 (- 1) = 21

x_{1, 2} = \frac{- ( - 1 ) \pm 21}{2 \cdot 5}

Separate the solutions

x_{1} = \frac{- ( - 1 ) + 21}{2 \cdot 5}, x_{2} = \frac{- ( - 1 ) - 21}{2 \cdot 5}

x = \frac{- ( - 1 ) + 21}{2 \cdot 5} : \frac{1 + 21}{10}

x = \frac{- ( - 1 ) - 21}{2 \cdot 5} : \frac{1 - 21}{10}

The solutions to the quadratic equation are:

x = \frac{1 + 21}{10}, x = \frac{1 - 21}{10}

5 (- 6 + n) = - 60

3 x + 7 = 25

\frac{x ^{2} - 9 x y - 10 y ^{2}}{x + y}

\frac{3 ^{4}}{3 ^{- 2}}

(2 - x)^{2}

What are the solutions to the equation 5x^2-x-1=0 ?
The solutions to the equation 5x^2-x-1=0 are x=(1+sqrt(21))/(10),x=(1-sqrt(21))/(10)
Find the zeros of 5x^2-x-1=0
The zeros of 5x^2-x-1=0 are x=(1+sqrt(21))/(10),x=(1-sqrt(21))/(10)