What are the solutions to the equation y^2-17y+16=0 ?

The solutions to the equation y^2-17y+16=0 are y=16,y=1

Find the zeros of y^2-17y+16=0

The zeros of y^2-17y+16=0 are y=16,y=1

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

y^{2} - 17 y + 16 = 0

y = 16, y = 1

Solution steps

y^{2} - 17 y + 16 = 0

Solve with the quadratic formula

y_{1, 2} = \frac{- ( - 17 ) \pm ( - 17 ) ^{2} - 4 \cdot 1 \cdot 16}{2 \cdot 1}

(- 17)^{2} - 4 \cdot 1 \cdot 16 = 15

y_{1, 2} = \frac{- ( - 17 ) \pm 15}{2 \cdot 1}

Separate the solutions

y_{1} = \frac{- ( - 17 ) + 15}{2 \cdot 1}, y_{2} = \frac{- ( - 17 ) - 15}{2 \cdot 1}

y = \frac{- ( - 17 ) + 15}{2 \cdot 1} : 16

y = \frac{- ( - 17 ) - 15}{2 \cdot 1} : 1

The solutions to the quadratic equation are:

y = 16, y = 1

x = lo g_{5} (25)

lo g_{12} (16)

714

4 x^{2} - 4 x + 17 = 0

2 u - 11 \leq 5 u + 6

What are the solutions to the equation y^2-17y+16=0 ?
The solutions to the equation y^2-17y+16=0 are y=16,y=1
Find the zeros of y^2-17y+16=0
The zeros of y^2-17y+16=0 are y=16,y=1