What is ((5x^4y^3))/(8x^5)*((3x^3y^5))/(6y^4) ?

The solution to ((5x^4y^3))/(8x^5)*((3x^3y^5))/(6y^4) is (5y^4x^2)/(16)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

simplify ((5x^4y^3))/(8x^5)*((3x^3y^5))/(6y^4)

simplify

\frac{( 5 x ^{4} y ^{3} )}{8 x ^{5}} \cdot \frac{( 3 x ^{3} y ^{5} )}{6 y ^{4}}

\frac{5 y ^{4} x ^{2}}{16}

Solution steps

\frac{5 x ^{4} y ^{3}}{8 x ^{5}} \cdot \frac{3 x ^{3} y ^{5}}{6 y ^{4}}

Cancel

\frac{5 x ^{4} y ^{3}}{8 x ^{5}} : \frac{5 y ^{3}}{8 x}

= \frac{5 y ^{3}}{8 x} \cdot \frac{3 x ^{3} y ^{5}}{6 y ^{4}}

Cancel

\frac{3 x ^{3} y ^{5}}{6 y ^{4}} : \frac{x ^{3} y}{2}

= \frac{5 y ^{3}}{8 x} \cdot \frac{x ^{3} y}{2}

Apply the fraction rule:

\frac{a}{b} \cdot \frac{c}{d} = \frac{a \cdot c}{b \cdot d}

= \frac{5 y ^{3} x ^{3} y}{8 x \cdot 2}

Simplify

\frac{x ^{3}}{x} : x^{2}

= \frac{5 y ^{3} x ^{2} y}{8 \cdot 2}

Simplify

y^{3} y : y^{4}

= \frac{5 y ^{4} x ^{2}}{8 \cdot 2}

Multiply the numbers:

8 \cdot 2 = 16

= \frac{5 y ^{4} x ^{2}}{16}

3 (x - 2) > 15

\frac{3 x - 5}{2} = 6

(24 c)^{\frac{2}{3}}

5 = \frac{3 x + 19}{2}

- 1 = - 3 r + 2 r

What is ((5x^4y^3))/(8x^5)*((3x^3y^5))/(6y^4) ?
The solution to ((5x^4y^3))/(8x^5)*((3x^3y^5))/(6y^4) is (5y^4x^2)/(16)