What is mn^2*m^2n^{-4}*mn^{-1} ?

The solution to mn^2*m^2n^{-4}*mn^{-1} is (m^4)/(n^3)

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simplify mn^2m^2n^{-4}mn^{-1}

simplify

m n^{2} \cdot m^{2} n^{- 4} \cdot m n^{- 1}

\frac{m ^{4}}{n ^{3}}

Solution steps

m n^{2} m^{2} n^{- 4} m n^{- 1}

Simplify

m m^{2} m : m^{4}

= m^{4} n^{2} n^{- 4} n^{- 1}

Simplify

n^{2} n^{- 4} n^{- 1} : \frac{1}{n ^{3}}

= m^{4} \frac{1}{n ^{3}}

Simplify

m^{4} \frac{1}{n ^{3}} : \frac{m ^{4}}{n ^{3}}

= \frac{m ^{4}}{n ^{3}}

2 x^{2} - 9 x + 5 = 0

\frac{x - 1}{3} = 3

\frac{a ^{3} b ^{5}}{a b ^{2}}

(x - 6) (x - 3) (x + 1) > 0

(3 - 42) (5 - 62)

What is mn^2*m^2n^{-4}*mn^{-1} ?
The solution to mn^2*m^2n^{-4}*mn^{-1} is (m^4)/(n^3)