What are the solutions to the equation 40=-16t^2+70t+5 ?

The solutions to the equation 40=-16t^2+70t+5 are t=(35-sqrt(665))/(16),t=(35+sqrt(665))/(16)

Find the zeros of 40=-16t^2+70t+5

The zeros of 40=-16t^2+70t+5 are t=(35-sqrt(665))/(16),t=(35+sqrt(665))/(16)

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40 = - 16 t^{2} + 70 t + 5

t = \frac{35 - 665}{16}, t = \frac{35 + 665}{16}

Decimal Notation

t = 0.57577 \dots, t = 3.79922 \dots

Solution steps

40 = - 16 t^{2} + 70 t + 5

Switch sides

- 16 t^{2} + 70 t + 5 = 40

Move

40

to the left side

- 16 t^{2} + 70 t - 35 = 0

Solve with the quadratic formula

t_{1, 2} = \frac{- 70 \pm 7 0 ^{2} - 4 ( - 16 ) ( - 35 )}{2 ( - 16 )}

7 0^{2} - 4 (- 16) (- 35) = 2665

t_{1, 2} = \frac{- 70 \pm 2 665}{2 ( - 16 )}

Separate the solutions

t_{1} = \frac{- 70 + 2 665}{2 ( - 16 )}, t_{2} = \frac{- 70 - 2 665}{2 ( - 16 )}

t = \frac{- 70 + 2 665}{2 ( - 16 )} : \frac{35 - 665}{16}

t = \frac{- 70 - 2 665}{2 ( - 16 )} : \frac{35 + 665}{16}

The solutions to the quadratic equation are:

t = \frac{35 - 665}{16}, t = \frac{35 + 665}{16}

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- 6 < 2 + 2 x < 8

100 \cdot 0.0 4^{2} = 0.0032 \cdot v^{2}

What are the solutions to the equation 40=-16t^2+70t+5 ?
The solutions to the equation 40=-16t^2+70t+5 are t=(35-sqrt(665))/(16),t=(35+sqrt(665))/(16)
Find the zeros of 40=-16t^2+70t+5
The zeros of 40=-16t^2+70t+5 are t=(35-sqrt(665))/(16),t=(35+sqrt(665))/(16)