What are the solutions to the equation 8+8x-x^2=0 ?

The solutions to the equation 8+8x-x^2=0 are x=-2(sqrt(6)-2),x=2(2+sqrt(6))

Find the zeros of 8+8x-x^2=0

The zeros of 8+8x-x^2=0 are x=-2(sqrt(6)-2),x=2(2+sqrt(6))

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8 + 8 x - x^{2} = 0

x = - 2 (6 - 2), x = 2 (2 + 6)

Decimal Notation

x = - 0.89897 \dots, x = 8.89897 \dots

Solution steps

8 + 8 x - x^{2} = 0

Write in the standard form

a x^{2} + b x + c = 0

- x^{2} + 8 x + 8 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 8 \pm 8 ^{2} - 4 ( - 1 ) \cdot 8}{2 ( - 1 )}

8^{2} - 4 (- 1) \cdot 8 = 46

x_{1, 2} = \frac{- 8 \pm 4 6}{2 ( - 1 )}

Separate the solutions

x_{1} = \frac{- 8 + 4 6}{2 ( - 1 )}, x_{2} = \frac{- 8 - 4 6}{2 ( - 1 )}

x = \frac{- 8 + 4 6}{2 ( - 1 )} : - 2 (6 - 2)

x = \frac{- 8 - 4 6}{2 ( - 1 )} : 2 (2 + 6)

The solutions to the quadratic equation are:

x = - 2 (6 - 2), x = 2 (2 + 6)

7 k^{2} + 21 k = 28

- 6 a < - 18

x^{2} - 8 x + 16 > 0

\frac{75}{20}

- 4 x^{2} - 5 x + 2 = 0

What are the solutions to the equation 8+8x-x^2=0 ?
The solutions to the equation 8+8x-x^2=0 are x=-2(sqrt(6)-2),x=2(2+sqrt(6))
Find the zeros of 8+8x-x^2=0
The zeros of 8+8x-x^2=0 are x=-2(sqrt(6)-2),x=2(2+sqrt(6))