What are the solutions to the equation 3t^2+4t-7=0 ?

The solutions to the equation 3t^2+4t-7=0 are t=1,t=-7/3

Find the zeros of 3t^2+4t-7=0

The zeros of 3t^2+4t-7=0 are t=1,t=-7/3

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3 t^{2} + 4 t - 7 = 0

t = 1, t = - \frac{7}{3}

Decimal Notation

t = 1, t = - 2.33333 \dots

Solution steps

3 t^{2} + 4 t - 7 = 0

Solve with the quadratic formula

t_{1, 2} = \frac{- 4 \pm 4 ^{2} - 4 \cdot 3 ( - 7 )}{2 \cdot 3}

4^{2} - 4 \cdot 3 (- 7) = 10

t_{1, 2} = \frac{- 4 \pm 10}{2 \cdot 3}

Separate the solutions

t_{1} = \frac{- 4 + 10}{2 \cdot 3}, t_{2} = \frac{- 4 - 10}{2 \cdot 3}

t = \frac{- 4 + 10}{2 \cdot 3} : 1

t = \frac{- 4 - 10}{2 \cdot 3} : - \frac{7}{3}

The solutions to the quadratic equation are:

t = 1, t = - \frac{7}{3}

(- 64)^{- \frac{3}{2}}

6 x^{4} + 3 x^{3} - 9 x^{2}

3 [- 2 (3) + 6 (2)]

x^{2} - 6 x = - 3

x^{5} y^{5} (- 14)

What are the solutions to the equation 3t^2+4t-7=0 ?
The solutions to the equation 3t^2+4t-7=0 are t=1,t=-7/3
Find the zeros of 3t^2+4t-7=0
The zeros of 3t^2+4t-7=0 are t=1,t=-7/3