What are the solutions to the equation 3x^2-15x+18=0 ?

The solutions to the equation 3x^2-15x+18=0 are x=3,x=2

Find the zeros of 3x^2-15x+18=0

The zeros of 3x^2-15x+18=0 are x=3,x=2

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3 x^{2} - 15 x + 18 = 0

x = 3, x = 2

Solution steps

3 x^{2} - 15 x + 18 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 15 ) \pm ( - 15 ) ^{2} - 4 \cdot 3 \cdot 18}{2 \cdot 3}

(- 15)^{2} - 4 \cdot 3 \cdot 18 = 3

x_{1, 2} = \frac{- ( - 15 ) \pm 3}{2 \cdot 3}

Separate the solutions

x_{1} = \frac{- ( - 15 ) + 3}{2 \cdot 3}, x_{2} = \frac{- ( - 15 ) - 3}{2 \cdot 3}

x = \frac{- ( - 15 ) + 3}{2 \cdot 3} : 3

x = \frac{- ( - 15 ) - 3}{2 \cdot 3} : 2

The solutions to the quadratic equation are:

x = 3, x = 2

\frac{60 - 59.933}{2}

2 s^{3} + 7 s^{2} + 21 s + 9

(ln (7))^{2}

4 n^{2} - 196

x = (\frac{64.61}{4}) (3.1415) (0.03288)^{2}

What are the solutions to the equation 3x^2-15x+18=0 ?
The solutions to the equation 3x^2-15x+18=0 are x=3,x=2
Find the zeros of 3x^2-15x+18=0
The zeros of 3x^2-15x+18=0 are x=3,x=2