What is factor 4x^2-19x-5 ?

The solution to factor 4x^2-19x-5 is (4x+1)(x-5)

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factor 4x^2-19x-5

factor

4 x^{2} - 19 x - 5

(4 x + 1) (x - 5)

Solution steps

4 x^{2} - 19 x - 5

Break the expression into groups

= (4 x^{2} + x) + (- 20 x - 5)

Factor out

x

from

4 x^{2} + x : x (4 x + 1)

Factor out

- 5

from

- 20 x - 5 : - 5 (4 x + 1)

= x (4 x + 1) - 5 (4 x + 1)

Factor out common term

4 x + 1

= (4 x + 1) (x - 5)

\frac{1}{2} (x^{2} + h) x

(z^{- \frac{4}{3}})^{- \frac{6}{5}}

4 n^{2} - 20 n + 25

6 x - 18 = 4 x + 23

(5)^{3}