What are the solutions to the equation x^2-5x=0 ?

The solutions to the equation x^2-5x=0 are x=5,x=0

Find the zeros of x^2-5x=0

The zeros of x^2-5x=0 are x=5,x=0

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x^{2} - 5 x = 0

x = 5, x = 0

Solution steps

x^{2} - 5 x = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 5 ) \pm ( - 5 ) ^{2} - 4 \cdot 1 \cdot 0}{2 \cdot 1}

(- 5)^{2} - 4 \cdot 1 \cdot 0 = 5

x_{1, 2} = \frac{- ( - 5 ) \pm 5}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 5 ) + 5}{2 \cdot 1}, x_{2} = \frac{- ( - 5 ) - 5}{2 \cdot 1}

x = \frac{- ( - 5 ) + 5}{2 \cdot 1} : 5

x = \frac{- ( - 5 ) - 5}{2 \cdot 1} : 0

The solutions to the quadratic equation are:

x = 5, x = 0

123 + 489 + x = 3213

k^{2} + 5 k + 4

(\frac{1}{4} x^{2})^{2}

18 x^{2} - 63 x

x^{2} + 62 x + 18 = 0

What are the solutions to the equation x^2-5x=0 ?
The solutions to the equation x^2-5x=0 are x=5,x=0
Find the zeros of x^2-5x=0
The zeros of x^2-5x=0 are x=5,x=0