What are the solutions to the equation 1-x^2=11-7x ?

The solutions to the equation 1-x^2=11-7x are x=2,x=5

Find the zeros of 1-x^2=11-7x

The zeros of 1-x^2=11-7x are x=2,x=5

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1 - x^{2} = 11 - 7 x

x = 2, x = 5

Solution steps

1 - x^{2} = 11 - 7 x

Move

7 x

to the left side

1 - x^{2} + 7 x = 11

Move

11

to the left side

- x^{2} + 7 x - 10 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 7 \pm 7 ^{2} - 4 ( - 1 ) ( - 10 )}{2 ( - 1 )}

7^{2} - 4 (- 1) (- 10) = 3

x_{1, 2} = \frac{- 7 \pm 3}{2 ( - 1 )}

Separate the solutions

x_{1} = \frac{- 7 + 3}{2 ( - 1 )}, x_{2} = \frac{- 7 - 3}{2 ( - 1 )}

x = \frac{- 7 + 3}{2 ( - 1 )} : 2

x = \frac{- 7 - 3}{2 ( - 1 )} : 5

The solutions to the quadratic equation are:

x = 2, x = 5

5 (7 - y) + 8 y \leq 17

7 \cdot 1 0^{- 5} e^{\frac{2.04}{( 8.62 \cdot 1 0 ^{- 5} ) ( 875 + 273 )}}

8 x^{3} + 4 x^{2} - 2 x - 1

8 x^{4} < 9 x^{3}

8^{3}

What are the solutions to the equation 1-x^2=11-7x ?
The solutions to the equation 1-x^2=11-7x are x=2,x=5
Find the zeros of 1-x^2=11-7x
The zeros of 1-x^2=11-7x are x=2,x=5