What are the solutions to the equation x^2+11x=-5x-60 ?

The solutions to the equation x^2+11x=-5x-60 are x=-6,x=-10

Find the zeros of x^2+11x=-5x-60

The zeros of x^2+11x=-5x-60 are x=-6,x=-10

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x^{2} + 11 x = - 5 x - 60

x = - 6, x = - 10

Solution steps

x^{2} + 11 x = - 5 x - 60

Move

60

to the left side

x^{2} + 11 x + 60 = - 5 x

Move

5 x

to the left side

x^{2} + 16 x + 60 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 16 \pm 1 6 ^{2} - 4 \cdot 1 \cdot 60}{2 \cdot 1}

1 6^{2} - 4 \cdot 1 \cdot 60 = 4

x_{1, 2} = \frac{- 16 \pm 4}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 16 + 4}{2 \cdot 1}, x_{2} = \frac{- 16 - 4}{2 \cdot 1}

x = \frac{- 16 + 4}{2 \cdot 1} : - 6

x = \frac{- 16 - 4}{2 \cdot 1} : - 10

The solutions to the quadratic equation are:

x = - 6, x = - 10

2 x^{3} + 3 x^{2} - 11 x - 6

14 d^{2} + 3 d - 2

(p - 3)^{3} - 1

8 \leq ∣ 4 x - 16 ∣

3 x^{3} - 12 x^{2} - 36 x

What are the solutions to the equation x^2+11x=-5x-60 ?
The solutions to the equation x^2+11x=-5x-60 are x=-6,x=-10
Find the zeros of x^2+11x=-5x-60
The zeros of x^2+11x=-5x-60 are x=-6,x=-10