What is the answer to |k-10|=3 ?

The answer to |k-10|=3 is k=7\lor k=13

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|k-10|=3

∣ k - 10 ∣ = 3

k = 7 or k = 13

Solution steps

∣ k - 10 ∣ = 3

Apply absolute rule: If

∣ u ∣ = a, a > 0

then

u = a

u = - a

k - 10 = - 3 or k - 10 = 3

k - 10 = - 3 or k - 10 = 3

k = 7 or k = 13

- \frac{5}{2} a + 5 = 25

28 x^{2} - 65 x + 28

(\frac{a ^{- 8} b}{a ^{- 5} b ^{3}})^{- 3}

∣ x + 10 ∣ > 6

\frac{2 x + 4}{x + 2}