What are the solutions to the equation x^2-10x-25=0 ?

The solutions to the equation x^2-10x-25=0 are x=5(1+sqrt(2)),x=5(1-sqrt(2))

Find the zeros of x^2-10x-25=0

The zeros of x^2-10x-25=0 are x=5(1+sqrt(2)),x=5(1-sqrt(2))

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x^{2} - 10 x - 25 = 0

x = 5 (1 + 2), x = 5 (1 - 2)

Solution steps

x^{2} - 10 x - 25 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 10 ) \pm ( - 10 ) ^{2} - 4 \cdot 1 \cdot ( - 25 )}{2 \cdot 1}

(- 10)^{2} - 4 \cdot 1 \cdot (- 25) = 102

x_{1, 2} = \frac{- ( - 10 ) \pm 10 2}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 10 ) + 10 2}{2 \cdot 1}, x_{2} = \frac{- ( - 10 ) - 10 2}{2 \cdot 1}

x = \frac{- ( - 10 ) + 10 2}{2 \cdot 1} : 5 (1 + 2)

x = \frac{- ( - 10 ) - 10 2}{2 \cdot 1} : 5 (1 - 2)

The solutions to the quadratic equation are:

x = 5 (1 + 2), x = 5 (1 - 2)

(x + 5) \cdot (x - 4) \leq 6

a^{2} + 14 a + 45

5 - 4 x \geq 3 x - 9

11 x^{2} + 100 x - 100

34 3^{- \frac{1}{3}}

What are the solutions to the equation x^2-10x-25=0 ?
The solutions to the equation x^2-10x-25=0 are x=5(1+sqrt(2)),x=5(1-sqrt(2))
Find the zeros of x^2-10x-25=0
The zeros of x^2-10x-25=0 are x=5(1+sqrt(2)),x=5(1-sqrt(2))